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2x(1-3x)+5x(3-x)=17x-11x^2
We move all terms to the left:
2x(1-3x)+5x(3-x)-(17x-11x^2)=0
We add all the numbers together, and all the variables
-(17x-11x^2)+2x(-3x+1)+5x(-1x+3)=0
We multiply parentheses
-(17x-11x^2)-6x^2-5x^2+2x+15x=0
We get rid of parentheses
11x^2-6x^2-5x^2-17x+2x+15x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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